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Maths Test 008
Maths Test 008
Note
Test 008 covers chapter 7 of the Edexcel Maths AS course.
There is no time limit - the average person should complete the test in an hour and a half.
The test will remain available until midnight on 3 August 2020.
The test total is 140 marks.
- Simplify the fractions.
(20)
- \( \frac{3x^4 - 4x^3 - 6x}{2x} \)
- \( \frac{2x^2 + 2x - 40}{x^2 + 2x - 15} \)
- \( \frac{2x^2 + 7x + 6}{x^2 - 3x - 10} \)
- \( \frac{2x^2 - 5x - 3}{2x^2 - 9x + 9} \)
- \( \frac{6x^3 + 3x^2 - 84x}{6x^2 - 33x + 42} \)
- Divide each polynomial
(20)
- \( x^3 + x^2 - 7x - 15 \) by \( (x - 3) \)
- \( -5x^3 - 27x^2 + 23x + 30 \) by \( (x + 6) \)
- \( 4x^4 - 6x^3 + 10x^2 - 11x - 6 \) by \( (2x - 3) \)
- \( 2x^3 - 17x + 3 \) by \( (x + 3) \)
- \( 4x^4 - 3x^3 + 11x^2 - x - 1 \) by \( (4x + 1) \)
- Given \( f(x) = 3x^3 - 14x^2 - 47x - 14 \),
(10)
- find the remainder when \( f(x) \) is divided by \( 2x - 1 \)
- find the remainder when \( f(x) \) is divided by \( x + 2 \)
- factorise completely
- Divide then factorise completely
(10)
- \( x^3 - 1 \) by \( (x - 1) \)
- \( x^4 - 16 \) by \( (x + 2) \)
- Given \( f(x) = 2x^3 + 3x^2 - 8x + 3 \),
(20)
- show that \( (2x - 1) \) is a factor
- factorise completely
- write down the roots of \( f(x) = 0 \)
- \( f(x) = 4x^3 + 4x^2 - 11x - 6 \)
(20)
- use long division to show that \( (x + 2) \) is a factor of \( f(x) \)
- use the factor theorem to show that \( (x + 2) \) is a factor of \( f(x) \)
- factorise \( f(x) \) completely
- write down all the solutions to \( f(x) = 0 \)
- sketch \( f(x) \)
- Use deduction for each question.
(20)
- Prove that \( -3n^2 - 4n + 10 \) is negative for all values of n.
- The equation \( kx^2 + 3kx + 1 = 0 \), where k is a constant, has no real roots. Use deduction to prove that \( k \) satisfies the inequality
\( 0 \lt k \lt \frac{4}{9} \).
- Prove that \( (x - \frac{2}{x})^3 \equiv x^3 - 6x + \frac{12}{x} - \frac{8}{x^3} \)
- Find a counter-example to disprove each of the following statements.
(20)
- if \( n \) is a positive integer, then \( n^4 - n \) is divisible by 4.
- \( 2n^2 - 6n + 1 \) is positive for all values of \( n \)
- \( a + \frac{1}{a} \ge 2 \)
- \( p + q \ge \sqrt{4pq} \)
- integers always have an odd number of factors
End of Maths Test 008
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